Question 139456
taking log __ (2x+5)log(2)=(x-48)log(3)


distributing __ 2xlog(2)+5log(2)=xlog(3)-48log(3)


subtracting xlog(3)+5log(2) __ 2xlog(2)-xlog(3)=-48log(3)-5log(2)


factoring __ x[2log(2)-log(3)]=-48log(3)-5log(2)


dividing by 2log(2)-log(3) __ x=[-48log(3)-5log(2)]/[2log(2)-log(3)]