Question 138538
Given: {{{A = P e^(rt)}}}  r=0.1 How long to double??

{{{A = P e^(rt)}}} 
{{{2P = P e^(0.1*t)}}} 
{{{2 = e^(0.1*t)}}} 
{{{ln(2) = ln(e^(0.1*t))}}}
{{{0.69315 = 0.1*t}}}
{{{6.9315 = t }}}