SOLUTION: A woman is asked her weight. She, appropriately, replies (you should never ask a woman her weight � unless you are really asking for a slap in the face or a divorce) that she weigh

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Question 8876: A woman is asked her weight. She, appropriately, replies (you should never ask a woman her weight � unless you are really asking for a slap in the face or a divorce) that she weighs 60 lbs plus half her weight.
What is her actual weight (in lbs)?
Found 2 solutions by rapaljer, prince_abubu:
Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website!
The equation is based upon the fact that "Her weight is equal to 60 lbs. plus half her weight."

Srart by letting x = thw weight of the woman (if she is like most women I know, in this case, x is REALLY the unknown!)

"Her weight is equal to 60 lbs. plus half her weight."

You probably don't like that fraction, so just multiply both sides of the equation by 2 and get rid of it.

Subtract x from each side, and you get:

Check it out: Her weight is 120, which equals 60 plus half of her weight, which is another 60.

You might figure out a way to do this intuitively (like in your head), but I like equations. They are reliable!

R^2 at SCC

Answer by prince_abubu(198) (Show Source):
You can put this solution on YOUR website!
Say that her weight is that mysterious W. If she says that her weight is 60 pounds plus 1/2 of her weight, that's

<-------------- Start here

<---- subtract 0.5W from both sides

<----- combine like terms

<----- divide both sides by 0.5. She weighs 120 pounds.