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Question 88136:
Found 2 solutions by rapaljer, malakumar_kos@yahoo.com:
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = longer side (length)
x-3 = shorter side (width)

2L + 2W = P
2(x) + 2(x-3) = 54
2x+2x-6=54
4x-6= 54

Add +6 to each side:
4x-6+6=54+6
4x= 60
x=15 Length
x-3= 12 = Width

Check:
2(15) + 2(12 ) = 54
30+ 24= 54
It checks!

R^2

Answer by malakumar_kos@yahoo.com(315) About Me  (Show Source):
You can put this solution on YOUR website!

one side of a rectangle is 3 less than the other side and the perimeter is 54 inches long what are the dimensions of the rectangle?

Let the length of the rectangle be = l = x inc
the width of the rectangle will be = b = x-3 inc
perimeter of the rectangle is = p = 54 inc
p = 2(l+b)
54 = 2(x+x-3)
54/2 = 2x-3
27 = 2x-3 or 27+3 = 2x i.e, 2x = 30
x= 30/2 = 15
length of the rectangle = l = 15 inch
width of the rectangle = b = 15-3 = 12 inch