SOLUTION: The length of the rectangle is 3 times its width. The perimeter of the rectangle is 160 ft. Find the length and the width of the rectangle. Solve the problem algebraically.

Algebra ->  Inequalities -> SOLUTION: The length of the rectangle is 3 times its width. The perimeter of the rectangle is 160 ft. Find the length and the width of the rectangle. Solve the problem algebraically.      Log On


   

Question 87379: The length of the rectangle is 3 times its width. The perimeter of the rectangle is 160 ft. Find the length and the width of the rectangle. Solve the problem algebraically.
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
width = w
length = 3w
2*width + 2*length = perimeter
2(w) + 2(3w) = 160
2w + 6w = 160
8w = 160
w = 20
width = 20 feet
length = 60 feet