SOLUTION: a passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passanger train is 25 mi/phr faster than the speed fo the freight t
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-> SOLUTION: a passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passanger train is 25 mi/phr faster than the speed fo the freight t
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Question 81412: a passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passanger train is 25 mi/phr faster than the speed fo the freight train, find the speed of each. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passanger train is 25 mi/phr faster than the speed fo the freight train, find the speed of each.
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Passenger train DATA:
distance=25 mi ; rate = x mph ; time = d/r = 325/x hrs
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Freight train DATA:
distance = 200 m ; rate = x-25 mph ; time = d/r = 200/(x-25) hr
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EQUATION:
time = time
325/x = 200/(x-25
Crsoo- multiply to get:
325(x-25) = 200x
325x-8125 = 200x
125x = 8125
x = 65 mph ( speed of passenger train)
x-25 = 40mph(speed of freight train)
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Cheers,
Stan H.
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