SOLUTION: I have problem about probability. "You and your friend are playing on a recreational basketball team that has a total of 8 players. Five players will be chosen at random to start

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Question 749548: I have problem about probability.
"You and your friend are playing on a recreational basketball team that has a total of 8 players. Five players will be chosen at random to start the game. What is the probability that your fried will be chosen and you will not be chosen to start the game?
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I just don't know what to do here. I think that (1/8!) could work for something, but I don;t know for sure. Please help ASAP.
-Locke
Answer by KMST(5399) About Me  (Show Source):
You can put this solution on YOUR website!
There are 8%2A7%2A6%2A5%2A4%2F2%2F3%2F4%2F5=8%2A7%2A6%2F2%2F3=8%2A7=56 possible teams of 5 out of 8.
The number of teams that include your friend but not you is the number of sets of 4 players they can make from the other 6 player, which is
6%2A5%2A4%2F2%2F3%2F4=6%2A5%2F2%2F3=5
So 5 out of the 56 possible teams will include your friend, but not you.
The probability of that happening is
5%2F56
Are you the old Locke, or the fictional future Peter Wiggin?

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