SOLUTION: solve using Applications of a non linear system
Find the length and width of a rectangle whose perimeter is 20 feet and whose area is 21 square feet
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Find the length and width of a rectangle whose perimeter is 20 feet and whose area is 21 square feet
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Question 731786: solve using Applications of a non linear system
Find the length and width of a rectangle whose perimeter is 20 feet and whose area is 21 square feet
You can put this solution on YOUR website! Find the length and width of a rectangle whose perimeter is 20 feet and whose area is 21 square feet
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20 = 2(L + W)
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L*W = 21
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Equation:
L + W = 10
L*W = 21
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Substitute for "L" and solve for "W"
(10-W)W = 21
10W - W^2 = 21
W^2 - 10W + 21 = 0
Factor:
(W-3)(W-7) = 0
Width = 3 or Width = 7
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If Width = 3, then Length = 7
If Width = 7 then Length = 3
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Cheers,
Stan H.
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