SOLUTION: the sum of two positive integers is 4 times the smaller. the positive difference of their squares is 8 times the larger. what is the product of the two integers

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Question 655490: the sum of two positive integers is 4 times the smaller. the positive difference of their squares is 8 times the larger. what is the product of the two integers
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

the sum of two positive integershighlight%28x%29 and highlight%28y%29is 4 times the smallerhighlight%28x%29. 

Question states***

 x + y = 4x   Or y+=+3x

Question also states***

the positive difference of their squares is 8 times the larger

 y^2 - x^2 = 8y

 (3x)^2 - x^2 = 8(3x)

  9x^2 - x^2 = 24x

  8x^2 - 24x = 0

 8x(x - 3) = 0

 8x = 0 ,  x = 0   Toss out this solution (0 is not a positive integer)

0r 

(x - 3) = 0 , x = 3  and  y = 9

and...  81-9+=+72+=+8%2A9

Product of the two integers is 27