Question 635716: A can do half as much work as B in the same time and B can do one third as much work as C. If they can finish the work in 12 days, find in how many days can each finish the work.
Solution:
Let C does 1 work in x days, then
C = 1/x, B = 1/3x, A = 1/16x
Total work = 1
or, 12(1/x + 1/3x + 1/6x) = 1
Or, x = 1/18
So, C = 18 days, B = 54 days, C = 108 days. Am I right ? I am not sure.
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!
Hi,
Let C does 1 work in x days, then
C = 1/x, B = 1/3x, A = 1/6x
Total work = 1
or, 12(1/x + 1/3x + 1/6x) = 1
prefer to think of it in this manner: work/day
(1/x + 1/3x + 1/6x) = 1/12 |Multiplying thru by 12x so as all denominators = 1
12 + 4 + 2 = x
Or, x = 18
So, C = 18 days, B = 54 days, C = 108 days Yes. Good Work.
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