SOLUTION: (x^2+y^4)(x^2-y^4)
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Question 624889
:
(x^2+y^4)(x^2-y^4)
Answer by
jim_thompson5910(35256)
(
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):
You can
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(x^2+y^4)(x^2-y^4)
x^2(x^2-y^4)+y^4(x^2-y^4)
x^4-x^2y^4+x^2y^4-y^8
x^4-y^8
So (x^2+y^4)(x^2-y^4) =
x^4-y^8
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