SOLUTION: Find the dimensions of a photo that has an area of 48 sq. in and a perimeter of 28 in.

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Question 603785: Find the dimensions of a photo that has an area of 48 sq. in and a perimeter of 28 in.
Answer by mananth(16949) About Me  (Show Source):
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let length = x in
width = y in
Perimeter
2(x+y) = 28
x+y = 14
Area
xy = 48
x= 48/y
substitute x
x+y =14
48/y + y = 14
multiply equation by y
48+y^2=14y
y^2-14y+48=0
y^2-8y-6y+48=0
y(y-8)-6(y-8)=0
(y-8)(y-6)=0
y = 6 OR 8
the dimensions are 8 in by 6 in