SOLUTION: What is the slope of the line tangent to the curve 3y^2-2x^2=6-2xy at the point (3,2)?

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Question 587243: What is the slope of the line tangent to the curve 3y^2-2x^2=6-2xy at the point (3,2)?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the slope of the line tangent to the curve 3y^2-2x^2=6-2xy at the point (3,2)?
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3y^2-2x^2=6-2xy
6ydy - 4xdx = -2(xdy + ydx) = -2xdy - 2ydx
6ydy + 2ydy = -2ydx + 4xdx
4ydy = (2x - y)dx
dy/dx = (2x - y)/4y
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f'(3,2) = (6 - 2)/(4*2) = 1/2
Tangent line: 2y = x + 1