SOLUTION: At 10:00 a.m. pipe A began to fill an empty storage tank. At noon, pipe A malfunctioned and was closed. Pipe B was used to finish filling the tank. If pipe A needs 6h to fill the t
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-> SOLUTION: At 10:00 a.m. pipe A began to fill an empty storage tank. At noon, pipe A malfunctioned and was closed. Pipe B was used to finish filling the tank. If pipe A needs 6h to fill the t
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Question 548134: At 10:00 a.m. pipe A began to fill an empty storage tank. At noon, pipe A malfunctioned and was closed. Pipe B was used to finish filling the tank. If pipe A needs 6h to fill the tank alone and pipe B needs 8h, at what time was the tank full? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! First find out how much of the tank by
pipe A alone
10 AM to noon is 2 hrs
Pipe A's rate is ( 1 tank )/( 6 hrs ) of a tank
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There is 2/3 of the tank left to fill
Let = time in hrs for B to finish filling tank
B's rate is ( 1 tank ) / ( 8 hrs )
Multiply both sides by
The time used by both pipes is
This is 7 hrs and 20 min to fill the tank
