SOLUTION: What are four consecutive even integers such that the sum of the first and the third is six less than the largest?

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Question 525298: What are four consecutive even integers such that the sum of the first and the third is six less than the largest?
Found 2 solutions by oberobic, MathTherapy:
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
Four consecutive even integers could be defined as w, x, y, and z.
But then you would have 4 unknowns, so you would need 4 equations to solve the problem.
However, we're told they're consecutive even integers, so you can define them as
x, x+2, x+4, and x+6. Now you have only one unknown.
.
x + x+4 + 6 = x+6
.
2x = -4
x = -2
.
So the numbers are -2, 0, 2, and 4

Answer by MathTherapy(10858) About Me  (Show Source):
You can put this solution on YOUR website!
What are four consecutive even integers such that the sum of the first and the third is six less than the largest?

Let the 1st even integer be F

Then others are F + 2, F + 4, and F + 6

We then have: F + F + 4 = F + 6 - 6

2F + 4 = F

F = - 4

Therefore, the 4 even integers are highlight_green%28-4%29, highlight_green%28-2%29, highlight_green%280%29, and highlight_green%282%29

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Check
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Sum of 1st & 3rd: - 4 + 0, or - 4

Six (6) less than largest: 2 - 6, or - 4

Sum of 1st & 3rd (- 4) = 6 less than largest (- 4)

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