SOLUTION: A roofer requires 10 h to shingle a roof. After the roofer and an apprentice work on a roof for 6 h, the roofer moves on to another job. The apprentice requires 8 more hours to fin

Algebra ->  Rate-of-work-word-problems -> SOLUTION: A roofer requires 10 h to shingle a roof. After the roofer and an apprentice work on a roof for 6 h, the roofer moves on to another job. The apprentice requires 8 more hours to fin      Log On


   

Question 522450: A roofer requires 10 h to shingle a roof. After the roofer and an apprentice work on a roof for 6 h, the roofer moves on to another job. The apprentice requires 8 more hours to finish the job. How long would it take the apprentice, working alone, to do the job?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A roofer requires 10 h to shingle a roof.
After the roofer and an apprentice work on a roof for 6 h, the roofer moves on to another job.
The apprentice requires 8 more hours to finish the job.
How long would it take the apprentice, working alone, to do the job?
:
Let a = time required by the apprentice to do the job
Let the completed job = 1
:
From the given information, we know the roofer worked 6 hrs, the apprentice 14 hrs
:
Write a shared work equation
6%2F10 + 14%2Fa = 1
multiply 10a, results:
6a + 10(14) = 10a
140 = 10a - 6a
140 = 4a
a = 140%2F4
a = 35 hrs apprentice working alone
:
:
Check this out,
6%2F10 + 14%2F35 =
.6 + .4 = 1