SOLUTION: I need help with this problem!!! I am stuck and it's a test problem!!! Thank you! When fighting a fire, the velocity v of water being pumped into the air is modeled by the funct

Algebra ->  Radicals -> SOLUTION: I need help with this problem!!! I am stuck and it's a test problem!!! Thank you! When fighting a fire, the velocity v of water being pumped into the air is modeled by the funct      Log On


   

Question 520741: I need help with this problem!!! I am stuck and it's a test problem!!! Thank you!
When fighting a fire, the velocity v of water being pumped into the air is modeled by the function v= √2hg, where h represents the maximum height of the water and g represents the acceleration due to gravity (32 ft/s2).
The Islip Fire Department must purchase a pump that will propel water 90 feet into the air. Will a pump that is advertised to project water with a velocity of 77 feet per second meet the fire departments need? EXPLAIN mathematically and verbally.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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When fighting a fire, the velocity v of water being pumped into the air is modeled by the function v= √2hg, where h represents the maximum height of the water and g represents the acceleration due to gravity (32 ft/s2).
:
The Islip Fire Department must purchase a pump that will propel water 90 feet into the air.
Will a pump that is advertised to project water with a velocity of 77 feet per second meet the fire departments need? EXPLAIN mathematically and verbally.
:
Find the velocity required, replace h with 90 ft, g with 32 ft/s
v+=+sqrt%282%2A90%2A32%29
v = 75.86 ~ 76 ft/sec
therefore a pump with a 77 ft/sec will just do it
:
Find the actual height (h) that a pump with 77 ft/s is able accomplish
sqrt%282%2Ah%2A32%29 = 77
sqrt%2864h%29 = 77
square both sides
64h = 77^2
64h = 5929
h = 5929%2F64
h = 92.6 ft