SOLUTION: Please help me multiply this expression. (3x+3y)^2(2x+3y). I did the () first and got (9x^2+9y^2)(2x+3y). If I use the FOIL method then there are mixed variables. My confusion is n
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-> SOLUTION: Please help me multiply this expression. (3x+3y)^2(2x+3y). I did the () first and got (9x^2+9y^2)(2x+3y). If I use the FOIL method then there are mixed variables. My confusion is n
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Question 519343: Please help me multiply this expression. (3x+3y)^2(2x+3y). I did the () first and got (9x^2+9y^2)(2x+3y). If I use the FOIL method then there are mixed variables. My confusion is now what do I do? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! (3x+3y)^2*(2x+3y)
First FOIL
(3x + 3y)* (3x + 3y) = 9x^2 + 9xy + 9xy + 9y^2
Combine like terms and you have
9x^2 + 18xy + 9y^2
:
Multiply this by (2x+3y), but do it this way, long multiplication
9x^2 + 18xy + 9y^2
. . . . . . . . . 2x + 3y
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:
You should get: 18x^3 + 63x^y + 72xy^2 + 27y^3
Corrected to: 18x^3
