SOLUTION: find three consecutive even integers with the property that the second integer plus the third integer is 18 more than the first integer. how do you show work for this?

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Question 482494: find three consecutive even integers with the property that the second integer plus the third integer is 18 more than the first integer. how do you show work for this?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
let the three consecutive even integers be; x, (x+2), (x+4)
:
write an equation for the phrase:
"the second integer plus the third integer is 18 more than the first integer."
(x+2) + (x+4) = x + 18
2x + 6 = x + 18
2x - x = 18 - 6
x = 12, then 14 and 16 are next even integers
:
Check that in the statement;
the second integer plus the third integer is 18 more than the first integer."
14 + 16 = 12 + 18
:
Not that hard, right?