SOLUTION: {{{ sqrt((x^2+2x-8)/x))}}} =x-2 What I have so far: x^2+2x-8/x = (x-2)(x-2)

Algebra ->  Square-cubic-other-roots -> SOLUTION: {{{ sqrt((x^2+2x-8)/x))}}} =x-2 What I have so far: x^2+2x-8/x = (x-2)(x-2)       Log On


   

Question 472050: +sqrt%28%28x%5E2%2B2x-8%29%2Fx%29%29 =x-2
What I have so far: x^2+2x-8/x = (x-2)(x-2)
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
+sqrt%28%28x%5E2%2B2x-8%29%2Fx%29%29 =x-2
x^2+2x-8/x = (x-2)(x-2)
x^2+2x-8/x = x^2-4x+4
x^2+2x-8=x^3-4x^2+4x
x^3-5x^2+2x+8=0
(x+4)(x-2)(x+1)=0
x=2 The only answer.
.
Ed