Question 458666: What is the point-slope form of an equation of the line that passes through (4,-3) and (2,1)? Found 2 solutions by rfer, stanbon:Answer by rfer(16322) (Show Source):
You can put this solution on YOUR website! slope
m=(1--3)/(2-4)
m=4/-2
m=-2
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y=mx+b
1=-2*2+b
1=-4+b
b=5
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y=-2x+5
You can put this solution on YOUR website! What is the point-slope form of an equation of the line that passes
through (4,-3) and (2,1)?
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To use the point-slope form you need the slope.
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slope + (1--3)/(2-4) = 4/-2 = -2
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Point-slope form using point (2,1):
y-y1 = m(x-x1)
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y-1 = -2(x-2)
y = -2x + 5
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Cheers,
Stan H.
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