SOLUTION: Trying to help my little brother with his homework, with little success.
Pipes A and B take 8 hours to fill a pool. Pipe A is twice the size of pipe B. How long would it take to
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Pipes A and B take 8 hours to fill a pool. Pipe A is twice the size of pipe B. How long would it take to
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Question 451383: Trying to help my little brother with his homework, with little success.
Pipes A and B take 8 hours to fill a pool. Pipe A is twice the size of pipe B. How long would it take to fill the pool using only pipe A?
We believe 2 + 2b = 8 would be a logical starting place, but don't know where to go from there.
Thanks for any help. Found 2 solutions by jorel1380, edjones:Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! If pipe A is twice as big as pipe B, then it is safe to assume that pipe B takes twice as long as pipe A to fill the pool. Therefore:
Pipe A + Pipe B=1/8 pool per hour
1/t+1/2t=1/8
8+4=t
t=12
Pipe A takes 12 hours to fill the pool alone; pipe B takes 24 hours to fill the pool alone..
You can put this solution on YOUR website! a takes a hrs to fill the pool. b takes 2a hrs.
a fills 1/a of the pool in 1 hr. b fills 1/2a of the pool in 1 hr.
1/a + 1/2a = 1/8
8+4=a multiply each side by 8a
a=12 hrs
.
Ed
