Question 441910: given the amount (oz) of juice in 10 randomly selected juice bottles are:
15.1, 15.6, 15.6, 15.9, 15.2, 15.9, 15.2,15.1, 15.8, 15.2.
construct a 94% confidence interval for the mean amount of the juice, u(with a wierd line), in the population of all such bottles. assume that the population has a normal distribution.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In a sample of 60 mice, a biologist found that 46% were able to run a maze in 30 seconds or less. Find the 90% limit for the population proportion of mice who can run that maze in 30 seconds or less?
---------------------------
p-hat = 0.46
ME = 1.645*sqrt[0.46*0.54/60] = 0.1058
-----------
90% CI: 0.46-0.1058 < p < 0.46+0.1058
=========================================
Cheers,
Stan H.
|
|
|
