Question 408433: traveling at a rate of 60 miles per hour , Teo drives past the Meadville rest area. Thirty minutes later Sierra drives past the same rest area at a rate of 70 miles per hour. If Teo and Sierra continue to travel at their current rate , how long will it take Sierra to catch up with Teo?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! traveling at a rate of 60 miles per hour, Teo drives past the Meadville rest area.
Thirty minutes later Sierra drives past the same rest area at a rate of 70 miles per hour.
If Teo and Sierra continue to travel at their current rate, how long will it take Sierra to catch up with Teo?
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Let t = time required for S to catch T
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Change 30 min to .5 hrs
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From the given information, we know that when T passed the rest area, S is 30 min behind T.
At 70 mph we know; .5 * 70 = 35, therefore, S is 35 mi behind T at this time.
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When S catches t, S has traveled 35 mi further than T,
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Write a distance equation; dist = speed * time
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S dist = T dist + 35 mi
70t = 60t + 35
70t - 60t = 35
10t = 35
t = 
t = 3.5 hrs for S to catch T
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Check this by finding the actual dist each traveled in 3.5 hrs
3.5*70 = 245 mi
3.5*60 = 210 mi
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differ: 35 mi
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