SOLUTION: college algebra - factoring quadratic quations
i want to make sure i have my signs correct at the end
x^2-4-12=0
(x-2) (x-6)
x-2=0 x-6=0
+2 +2 +6 +6
x=2 x=6
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-> SOLUTION: college algebra - factoring quadratic quations
i want to make sure i have my signs correct at the end
x^2-4-12=0
(x-2) (x-6)
x-2=0 x-6=0
+2 +2 +6 +6
x=2 x=6
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Question 405830: college algebra - factoring quadratic quations
i want to make sure i have my signs correct at the end
x^2-4-12=0
(x-2) (x-6)
x-2=0 x-6=0
+2 +2 +6 +6
x=2 x=6
Can i have both answers positive? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! x^2-4x-12=0
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(x-6)(x+2) = 0
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x = 6 or x = -2
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Cheers,
Stan H.
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