You can put this solution on YOUR website! x+4y=19
5x+y+0
Let's solve this one by elimination method. Multiply the second equation by 4, then subtract it from the first equation:
x+4y = 19
20x +4y = 0
-----------
-19x = 19
x= -1
Plug this value into either equation to find y:
5x+y = 0
5(-1) + y = 0
-5 + y = 0
y = 5
So the solution is (-1,5) or x=-1, y=5.
Second question is weird because it has no nice answers. Are you supposed to write your answers as fractions or as decimals? I did it with fractions:
a-b=25
3a+4b=4
Multiply the first equation by 3, then subtract.
