SOLUTION: How can you have one solution in something that is quadratic?
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Question 384398
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How can you have one solution in something that is quadratic?
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When b^2 - 4ac is equal to 0, you will have 1 solution.
The standard form of the quadratic equation is:
ax^2 + bx + c = 0
a is the coefficient of the x^2 term.
b is the coefficient of the x term.
c is the constant term.
To find the roots of this equation, you can use the quadratic formula.
the quadratic formula is:
x = -b +/- sqrt(b^2-4ac) -------------------- 2a
If b^2 - 4ac is equal to 0, then you have +/- 0 in the numerator and there is only one solution to the problem.
We can construct an example to show you what I mean.
To construct this example, let's pick a b term at random.
Let's say b is equal to 6.
That makes b^2 = 36
Divide 36 by 4 to get 9.
We need to get a * c to be equal to 9.
a * c will be equal to 9 when a = 1 and c = 9
We have:
a = 1
b = 6
c = 9
b^2 - 4ac becomes 36 - (4*1*9) which becomes 36 - 36 which becomes 0.
Our quadratic equation should have one solution only.
The standard form of the quadratic equation is ax^2 + bx + c = 0
Since a = 1, b = 6 and c = 9, this equation becomes:
x^2 + 6x + 9 = 0
We will now graph this equation as shown below:
You can see from the graph that the graph of the quadratic equation touches the x-axis at the point x = -3 and only at that point.