SOLUTION: Hi Please help,
Obtain the Maclaurin series expansion about the point 0 for the function ln(x+1) as
ln(x + 1) = x-x^2/2+x^3/3+(1)^n+1x^n/n + ...
Note that we cannot
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Sequences-and-series
-> SOLUTION: Hi Please help,
Obtain the Maclaurin series expansion about the point 0 for the function ln(x+1) as
ln(x + 1) = x-x^2/2+x^3/3+(1)^n+1x^n/n + ...
Note that we cannot
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Obtain the Maclaurin series expansion about the point 0 for the function ln(x+1) as
ln(x + 1) = x-x^2/2+x^3/3+(1)^n+1x^n/n + ...
Note that we cannot find a Maclaurin expansion of the function ln x since ln x does not exist at x = 0 and so
cannot be differentiated at x = 0.
Thank You in advance
Matt
You can put this solution on YOUR website! I think I have solved this exact same question previously on this website. Here is my solution:
This is equivalent to finding the power series of ln x centered around x = 1. Note that all derivatives of ln x at x = 1 are equal to 1 or -1. Since we have the power series
Adding one to all the x terms produces the given result.
