SOLUTION: The area of a rectangle is 15 square feet. The width can be represented by x - 3.5 and the length by 'x'. What are the dimensions of the rectangle?
I've tried this problem a doz
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-> SOLUTION: The area of a rectangle is 15 square feet. The width can be represented by x - 3.5 and the length by 'x'. What are the dimensions of the rectangle?
I've tried this problem a doz
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Question 380097: The area of a rectangle is 15 square feet. The width can be represented by x - 3.5 and the length by 'x'. What are the dimensions of the rectangle?
I've tried this problem a dozen times. I don't know what it is I'm doing wrong. Found 2 solutions by richard1234, mananth:Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! The area is just (x)(x - 3.5) = 15 -->
x = -5/2 or x = 6. We take the positive value x = 6 and check: 6(6 - 3.5) = 15.
You can put this solution on YOUR website! wid th = x-3.5
length =x
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Area = l*w
x(x-3.5)=15
x^2-3.5x=15
multiply by 2
2x^2-7x=30
-30
2x^2-7x-30=0
2x^2-12x+5x-30=0
2x(x-6)+5(x-6)=0
(2x+5)(x-6)=0
x= 6 feet, the length
x-3.5
=6-3.5 = 2.5 feet, the width.
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CHECK
Area = l*w
6*2.5 = 15
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m.ananth@hotmail.ca
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