SOLUTION: How many litres of a 12% alcohol solution must be mixed with 8 litres of a 3% alcohol solution to make a 9% solution 12x/100 + 8 . 3 / 100 = (x + 8 ). 9 / 100 12x + 24

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Question 362372: How many litres of a 12% alcohol solution must be mixed with 8 litres of a 3% alcohol solution to make a 9% solution
12x/100 + 8 . 3 / 100 = (x + 8 ). 9 / 100
12x + 24 = 9(x+8)
3x = 48
x = 16
Found 3 solutions by Fombitz, mananth, tessmaths:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the number of liters of 12% solution.
12%28A%29%2B3%288%29=9%28A%2B8%29
12A%2B24=9A%2B72
3A=48
highlight%28A=16%29 liters

Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
12% alcohol solution - x litres
mixed with 8 litres of a 3%
mix 9% solution (x+8)litres
..
0.12x+8*0.03=0.09(x+8)
0.12x+0.24=0.09x+0.72
0.03x=0.72-0.24
0.03x=0.48
x=0.48/0.03
x=16 litres of 12% alchohol
...
m.ananth@hotmail.ca

Answer by tessmaths(2) About Me  (Show Source):
You can put this solution on YOUR website!
How many litres of a 12% alcohol solution must be mixed with 8 litres of a 3% alcohol solution to make a 9% solution
12x/100 + 8 . 3 / 100 = (x + 8 ). 9 / 100
12x + 24 = 9(x+8)
3x = 48
x = 16