SOLUTION: Find two numbers, given that the second is 3 times the first. If you multiply the first number by the second number and the second number by 4, the sum of the products is 420.

Algebra ->  Human-and-algebraic-language -> SOLUTION: Find two numbers, given that the second is 3 times the first. If you multiply the first number by the second number and the second number by 4, the sum of the products is 420.      Log On


   

Question 34443: Find two numbers, given that the second is 3 times the first. If you multiply the first number by the second number and the second number by 4, the sum of the products is 420.
Answer by venugopalramana(3286) About Me  (Show Source):
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Find two numbers, given that the second is 3 times the first. If you multiply the first number by the second number and the second number by 4, the sum of the products is 420.
LET FIRST NUMBER =X
SEOND NUMBER =3 TIMES FIRST =3*X
MULTIPLY THE FIRST NUMBER BY SECOND WE GET =X*3X=3X^2
MULTIPLY SECOND NUMBER BY 4 WE GET =4*3*X=12X
SUM OF 2 PRODUCTS =3X^2+12X=420...DIVIDING WITH 3 WE GET
X^2+4X=140
X^2+4X-140=0
X^2+14X-10X-140=0
X(X+14)-10(X+14)=0
(X-10)(X+14)=0
X-10=0 ....OR....X=10
SO THE 2 NUMBER ARE 10 AND 30....
OTHER POSSIBILITY IS X+14=0...OR X=-14...THE SECOND NUMBER IS -42