SOLUTION: If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ? (A) 700 (B) 2800 (C) 4000 (D) 7000 (E) 2

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ? (A) 700 (B) 2800 (C) 4000 (D) 7000 (E) 2      Log On

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Question 340443: If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2800
(C) 4000
(D) 7000
(E) 28000

Could you please explain the above problem.

Thanks
Found 2 solutions by Fombitz, solver91311:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The largest two digit number that x can be is 99.
The largest two digit number that y can be is 69.
The product xy is equal to 6831.
D is the closest answer.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


If is a two digit integer that is greater than 40, the largest it could be would be 99. If is an integer and less than 70, the largest it could be is 69. 69 times 99 is a little bit less than 70 times 100 = 7000.

John

My calculator said it, I believe it, that settles it