SOLUTION: Please help with this problem. It has been over 20 years since I have had Algebra and need a little refresher. Her is the story problem: Because of a noisy neighbor, a young m

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Question 338562: Please help with this problem. It has been over 20 years since I have had Algebra and need a little refresher.
Her is the story problem:
Because of a noisy neighbor, a young man decided to put acousinal tiles on the living room ceiling which measures 21 feet by 18 feet. The tiles are square, with a side length of 1 foot. If the tiles cost $3 a piece, what is the total cost to cover the ceiling?
Put in either 4,6,8.
Thank you!
My e-mail address is makaylasmum@yahoo.com
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Find the total area to cover the ceiling.
The ceiling is in the shape of a rectangle.
The area of a rectangle is length times width.
A=L%2AW=21%2A18sq.ft.
Each tile is a 1'x1' square and has an area of 1 sq. ft.
Divide the total area by the area of one tile to find out how many tiles you need.
N=A%2F1
The total cost is $3 times the number of tiles.
C=3N=%283A%29%2F1=%283%2A21%2A18%29%2F1 in dollars.