SOLUTION: if i am teatching a class how would i teatch them how to solve 3-5(x+2)=3(x+1)+6 please include your work at each step of the process along with the final answer.

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Question 335017: if i am teatching a class how would i teatch them how to solve 3-5(x+2)=3(x+1)+6
please include your work at each step of the process along with the final answer.
Found 2 solutions by tinbar, stanbon:
Answer by tinbar(133) About Me  (Show Source):
You can put this solution on YOUR website!
firstly, you should probably not teach the class if you can't solve this question on your own
secondly, the solution: you would tell your students this is an equation with only one variable to solve and to solve it, we need to group common terms together and simplify as best as we can
3-5(x+2)=3(x+1)+6
3-(5x+10)=(3x+3)+6
3-5x-10=3x+3+6
-7-5x=3x+9
...now the tricky part, we need to have all the x's on one side and anything not x on the other, in this case, i'm going to move all x's to the left side and anything else to the right
-5x-3x=9+7
-8x=16
x=16/-8
x=-2
now to check that this satisfies the original question on both sides
left side: 3-5(-2+2)=3-5(0) = 3
right side: 3(-2+1)+6 = 3(-1)+6 = -3+6 = 3
x=-2 works!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
if i am teatching a class how would i teach them how to solve
3-5(x+2)=3(x+1)+6
-------------------
Your Problem:
3-5(x+2)=3(x+1)+6
Explain the distributive law
and apply it to the parentheses
on the left and on the right side
to get:
3-5x-10 = 3x+3+6
-----
Simplify each side by combining "like" terms.
-5x-7 = 3x+9
-----
Add 5x to both sides to get:
-7 = 8x+9
Subtract 9 from both sides to get:
8x = -16
Divide both sides by 8 to get:
x = -2
-----------------------------------------------
Teach the students how to check their answers so
they will know if their answers are correct.
3-5(x+2)=3(x+1)+6
Substitute -2 for "x":
3-(-2+2) = 3(-2+1)+6
3-0 = 3(-1)+6
3 = -3+6
3 = 3
=====================
Tell the students this means they have found
a numerical value that makes the original
equal true when it is substituted for the
letter "x".
=====================
Cheers,
Stan H.
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