SOLUTION: The width of a rectangle is 3 less than the length. If the perimeter is 50 meters, find the length and width..
Algebra ->
Rectangles
-> SOLUTION: The width of a rectangle is 3 less than the length. If the perimeter is 50 meters, find the length and width..
Log On
Question 324448: The width of a rectangle is 3 less than the length. If the perimeter is 50 meters, find the length and width.. Found 2 solutions by graphmatics, rfer:Answer by graphmatics(170) (Show Source):
You can put this solution on YOUR website! If x is the length of the rectangle then the width of the rectangle y = x-3. The perimeter is twice the width plus twice the length so 2*x + 2*(x-3) = 50. We solve this equation for x.
2*x + 2*(x-3) - 50
2*x + 2*x - 2*3 = 50
4*x -6 = 50
4*x = 50 + 6
4*x = 56
x - 56/4
x = 14
so y = 14 - 3
y = 11
So the length is 14 and the width is 11.
(