SOLUTION: If cement, gravel, and sand are to be mixed in the ratio of 3:5:7 respectively, and 5 tons of cement are available, how many tons of the mixture can be made? (Assume that enough gr

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: If cement, gravel, and sand are to be mixed in the ratio of 3:5:7 respectively, and 5 tons of cement are available, how many tons of the mixture can be made? (Assume that enough gr      Log On


   

Question 319979: If cement, gravel, and sand are to be mixed in the ratio of 3:5:7 respectively, and 5 tons of cement are available, how many tons of the mixture can be made? (Assume that enough gravel and sand are available to use all the available cement.)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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If cement, gravel, and sand are to be mixed in the ratio of 3:5:7 respectively, and 5 tons of cement are available, how many tons of the mixture can be made? (Assume that enough gravel and sand are available to use all the available cement.)
:
We can do it this way, let x = the multiplier
3x:5x:7x
:
Find the multiplier using the cement which was given
3x = 5
x = 5%2F3 is the multiplier
:
Gravel:5 *5%2F3 = 25%2F3 = 8.33 tons
Sand: 7 * 5%2F3 = 35%2F3 = 11.67 tons
:
Total mixture: 5 + 8.33 + 11.67 = 25 tons