SOLUTION: Solve the system: 3c-d=1 3d+c=1
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Question 317854
:
Solve the system:
3c-d=1
3d+c=1
Answer by
mananth(16949)
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1..3c-d=1
2..3d+c=1
..
multiply eq1 by 3
9c-3d=3
add to eq2
9c-3d+3d+c=4
10c=4
c=4/10 = 2/5
..
plug the value of c in eq1
3c-d=1
3*2/5-d=1
d=6/5 -1
d=6-5 / 5
d=1/5