SOLUTION: Sinem and Ekin leave the same point driving in opposite direction. Ekin's rate 12km/h more than Sinem's rate. After three hours they are 360km apart. Find the rate of each.
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-> SOLUTION: Sinem and Ekin leave the same point driving in opposite direction. Ekin's rate 12km/h more than Sinem's rate. After three hours they are 360km apart. Find the rate of each.
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Question 316289: Sinem and Ekin leave the same point driving in opposite direction. Ekin's rate 12km/h more than Sinem's rate. After three hours they are 360km apart. Find the rate of each. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! D=RT
360=(X+X+12)3
360=(2X-12)3
360=6X-36
6X=360+36
6X=324
X=324/6
X=54 km/h is Sinem's rate
54+12=66km/h is Ekin's rate.
Proof:
360=(54+66)3
360=120*3
360=360
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