SOLUTION: bill leaves nightclub at 60mph. sue leaves 1 minute later at 90mph. how many minutes before they meet?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: bill leaves nightclub at 60mph. sue leaves 1 minute later at 90mph. how many minutes before they meet?      Log On


   

Question 313676: bill leaves nightclub at 60mph. sue leaves 1 minute later at 90mph. how many minutes before they meet?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
D=60T FOR BILL.
D=90(T-1/60) FOR SUE.
60T=90(T-1/60)
60T=90T-90/60
60T-90T=-1.5
-30T=-1.5
T=-1.5/-30
T=.05 HOURS OR IN 3 MINUTES SUE WILL CATCH BILL.
PROOF:
60*.05=90(.05-1/60).
3=90(.05-.01667)
3=90*.0333
3=3