SOLUTION: Please answer this question for me: A missle is fired with an initial velocity of 1600 feet per second. When will it be 40,000 feet above the starting point?
The answer I got wa
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The answer I got wa
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Question 30292: Please answer this question for me: A missle is fired with an initial velocity of 1600 feet per second. When will it be 40,000 feet above the starting point?
The answer I got was: 25 seconds because I did 40000
------ = 25
I think its wrong though 1600 Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! SEE THE FOLLOWING AND DO
IN FPS SYSTEM ....G=32 FT/SEC^2..SO USE -32 INSTEAD OF -9.8 IN THE FOLLOWING
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PLEASE HELP ME A rocket is fired with an initial velocity of 800 meters per second. When will it be 32000 meters above the starting point?
Than answer I got was : 40 second because I divided... I think its wrong thought
AS THE ROCKET GOES UP AGAINST EARTHS GRAVITATIONAL FORCE , ITS VELOCITY REDUCES,GIVEN BY ACCELERATION DUE TO GRAVITY =-9.8 M/SEC^2..THE FORMULA TO BE USED IS
S = UT + (G/2)T^2....WHERE
U = INIYIAL VELOCITY = 800 M/SEC
T = TIME ELAPSED IN SECS.
G=ACCELERATION DUE TO GRAVITY = - 9.8 M/SEC^2 FOR UPWARD TRAVEL...SO..WE GET
32000 = 800T -(9.8/2)T^2=800T-4.9 T^2
4.9T^2-800T+32000 =0
T=70.1 WHILE GOING UP AND
T=93.2 WHILE FALLING DOWN.