SOLUTION: Here's my problem... The difference of the squares of two consecutive negative integers is 9. Find the integers. Here's what I have so far... -x and (-x+1) -x^2 and (-

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Here's my problem... The difference of the squares of two consecutive negative integers is 9. Find the integers. Here's what I have so far... -x and (-x+1) -x^2 and (-      Log On


   

Question 274402: Here's my problem...
The difference of the squares of two consecutive negative integers is 9. Find the integers.
Here's what I have so far...
-x and (-x+1)
-x^2 and (-x+1)^2
-x^2 - (-x+1)^2 = 9
-x^2 - (x + 1x + 1) = 9
-x^2 - x - 1x = 8
That's as far as I got and I'm not sure if that's correct.
Thanks again!!!

Found 2 solutions by stanbon, JBarnum:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Here's my problem...
The difference of the squares of two consecutive negative integers is 9. Find the integers.
---------------------
1st: x
2nd: x+1
--------------------
Equation:
(x+1)^2-x^2 = 9
x^2 + 2x + 1 - x^2 = 9
2x + 1 = 9
2x = 8
x = 4
x+1 = 5
===============
Cheers,
stan H.

Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
The difference of the squares of two consecutive negative integers is 9. Find the integers
-x%5E2-%28-x%2B1%29%5E2=9
-x%5E2%2B%28x-1%29%5E2=9
-x%5E2%2B%28x-1%29%28x-1%29=9
-x%5E2%2B%28x%5E2-x-x-1%29=9
-x%5E2%2Bx%5E2-2x-1=9
-2x-1=9
-2x=10
x=-5
intergers are x,(x+1) whith are -5,-4.
%28-5%5E2%29-%28-4%5E2%29=9
25-16=9
9=9
correct