SOLUTION: (x-1)(x^2+10x+24=0...This one has me baffled..I can work 2nd set of parentheses but the (x-1) has got me confused.Is this a valid solvable problem?

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Question 257734: (x-1)(x^2+10x+24=0...This one has me baffled..I can work 2nd set of parentheses but the (x-1) has got me confused.Is this a valid solvable problem?
Found 3 solutions by richwmiller, jsmallt9, drk:
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website!
The (x-1) is the easy part. You have to factor the rest into (x+4) (x+6)
which gives you three solutions.
x=1,-4 and -6

Answer by jsmallt9(3759)   (Show Source):
You can put this solution on YOUR website!

If you are trying to solve this equation, the presence of the (x-1) should not make any difference. This equation, if you were to multiply it out, would have an term. The most common way to find solutions to cubic equations is to make one side zero and factor the other side. Your equation, as it stands, already has one side equal to zero and the other side is partially factored. All we need to do is finish the factoring and then use the Zero Product Property.

The trinomial will factor making the equation:

Now we can use the Zero Product Property which tells us that this product can be zero only if one of the factors is zero. So
or or
Solving these simple equations we get:
or or
These are the solutions to the equation.

Answer by drk(1908)   (Show Source):
You can put this solution on YOUR website!
Here is the original question:

step 1 - factor the second polynomial to get

step 2 - set each pat = 0 and solve:
x-1 = 0
x = 1
x + 4 = 0
x = -4
x + 6 = 0
x = -6
we have three answers
{-6, -4, 1}