SOLUTION: Solving trigonomic equations algebraically, in terms of pi cot^2(x)=1 so far i got cot(x)=√1 then what?

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Question 244836: Solving trigonomic equations algebraically, in terms of pi
cot^2(x)=1
so far i got cot(x)=√1
then what?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Well remember that 1%5E2=1. So take the square root of both sides to get 1=sqrt%281%29. So taking the square root of 1 is just 1.

This gets you: cot%28x%29=1.


1%2Ftan%28x%29=1 Now use the identity cot%28x%29=1%2Ftan%28x%29


1=tan%28x%29 Multiply both sides by tan(x)


So tan%28x%29=1. Can you solve it from here? You'll need to use the unit circle if you're not familiar with all of the trig values.