SOLUTION: The product of two consecutive intergers is 19 more than their sum. find the numbers. This is the equation I came up with = x(x+2)=(x+x+2+19),but it works out to x to the second p

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The product of two consecutive intergers is 19 more than their sum. find the numbers. This is the equation I came up with = x(x+2)=(x+x+2+19),but it works out to x to the second p      Log On


   

Question 235767: The product of two consecutive intergers is 19 more than their sum. find the numbers.
This is the equation I came up with = x(x+2)=(x+x+2+19),but it works out to x to the second power minus 21. how do I factor it out?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
"The product of two consecutive intergers" ___ x(x+1)

"is" ___ =

"19 more than" ___ + 19

"their sum" ___ x + x+1

x(x+1) = x + x+1 + 19

x^2 + x = 2x + 20

x^2 - x - 20 = 0

(x + 4)(x - 5) = 0