SOLUTION: Set up a system of two equations with two variables to solve this problem. The three angles in a triangle always add up to 180 degrees. If one angle in a triangle is 132 degrees an

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Question 226250: Set up a system of two equations with two variables to solve this problem. The three angles in a triangle always add up to 180 degrees. If one angle in a triangle is 132 degrees and the second is 5 times the third, what are the three angles?
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Set up a system of two equations with two variables to solve this problem. The three angles in a triangle always add up to 180 degrees. If one angle in a triangle is 132 degrees and the second is 5 times the third, what are the three angles?

Step 1. Let x be the third angle.

Step 2. Let y=5x since the second is 5 times the third.

Step 3. Let x+y+132=180 since all three angles add up to 180 degrees. We can rewrite this after subtracting 132 from both side of the equation as

x%2By%2B132-132=180-132

x%2By=48

Step 4. The system of equations are

y=5x

x%2By=48

Step 5. Substitute y=5x into x%2By=48 to get x%2B5x=48}. Then

6x=48

Divide by 6 to both sides of the equation

6x%2F6=48%2F6

x=8 and y=5x=40. Also 132+8+40=180...as a check.

Step 6. ANSWER: The angles are 132, 8, and 40 degrees.


I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J

drjctu@gmail.com

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