SOLUTION: 9y^4+42y^3+49y^2
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Question 224534
:
9y^4+42y^3+49y^2
Answer by
rapaljer(4671)
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Assuming that you want to factor this, the first step is to take out the common factor of y^2:
9y^4+42y^3+49y^2
y^2(9y^2+42y+49)
What remains is actually a perfect square trinomial. The First times First is 3y*3y.
y^2(3y____)(3y_____)
The Last times Last is 7*7.
y^2(3y+7)(3y+7)
y^2(3y+7)^2
R^2