SOLUTION: If a, b are elements of the REAL numbers and a+b=0, then a= -b. I am having trouble with the steps, I kinda of know what types of axioms I need to use. Inverse and DEF. of Subtr

Algebra ->  Proofs -> SOLUTION: If a, b are elements of the REAL numbers and a+b=0, then a= -b. I am having trouble with the steps, I kinda of know what types of axioms I need to use. Inverse and DEF. of Subtr      Log On


   

Question 217826: If a, b are elements of the REAL numbers and a+b=0, then a= -b.
I am having trouble with the steps, I kinda of know what types of axioms I need to use. Inverse and DEF. of Subtraction are some of those.
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
If a, b are elements of the REAL numbers and a+b=0, then a= -b.
I am having trouble with the steps, I kinda of know what types of axioms I need to use. Inverse and DEF. of Subtraction are some of those.

Step 1. Given a%2Bb=0

Step 2. Add -b to both sides of the equation: a%2Bb-b=0-b

Step 3. Simplify to both sides of the equation to get: a=-b ANSWER

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
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