SOLUTION: Bob leaves at 9am heading due north at 9mph. Tom leaves at 9:30am heading due south at 4mph. At what time will Bob and Tom be 10 miles apart?
Question 213418: Bob leaves at 9am heading due north at 9mph. Tom leaves at 9:30am heading due south at 4mph. At what time will Bob and Tom be 10 miles apart? Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! Bob leaves at 9am heading due north at 9mph. Tom leaves at 9:30am heading due south at 4mph. At what time will Bob and Tom be 10 miles apart?
Step 1. Bob traveled for one-half hour before Tom leaves at 9:30 am. Let this distance be d0=9*0.5=4.5 miles.
Step 2. So Total Distance traveled by Bob dBob=4.5+9t where t is the amount of time at which Bob and Tom are 10 miles apart.
Step 3. Total Distance traveled by Tom is dTom = 4*t.
Step 4. But dBob+dTom = 10 miles
Step 5. So substitute equation in Steps 2 and 3 into Step 4.
Solving this equation will yield the following steps:
Cartoon (animation) form: For tutors: simplify_cartoon( 4.5+9t+4*t=10 )
If you have a website, here's a link to this solution.
DETAILED EXPLANATION
Look at . Moved to the right of expression It becomes . Look at . Eliminated similar terms, replacing them with It becomes . Look at . Added fractions or integers together It becomes . Look at . Remove unneeded parentheses around factor It becomes . Look at . Moved these terms to the left It becomes . Look at . Added fractions or integers together It becomes . Look at . Factors 55 and 10 have greatest common factor (GCF) of 5. Reducing fraction. It becomes . Look at . Solved linear equation equivalent to 13*t-5.5 =0 It becomes . Result: This is an equation! Solutions: t=0.423076923076923.
Universal Simplifier and Solver
Done!
Step 6. t=0.42307 hours or t = 0.42307*60 minutes/hour = 25.42 minutes.
Step 7. Time is therefore 9:30 am plus 25.42 minutes or 9:55 am.
I hope the above steps were helpful.
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.