SOLUTION: Text book Dugopolski, M. (2009). Elementary and intermediate algebra (3rd ed.) New York: McGraw-Hill Chapter 2 equations involving decimals. solve the equation by eliminatin

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Question 203216: Text book Dugopolski, M. (2009). Elementary and intermediate algebra (3rd ed.) New York: McGraw-Hill
Chapter 2

equations involving decimals.
solve the equation by eliminating the decimal numbers 0.08t +28.3 = 0.5t - 9.5
consecutive integers.
Four consecutive odd integers have a sum of 120. what are the integers?
I know that -60, -40, and -20 equals 120. would the worked out answer be:
x, (x+1) + (x+2) + (x + 3) = 120
4x + 4 = 120 combine like terms
4x = 116 subtract 4 from each side
x = 29 divide each side by 4
x + 1 = -30 if x = 29, then x + 1 is 30 and x + 2 = 31 The problem at this point is not making sense.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
1) Solve by eliminating the decmals:
0.08t%2B28.3+=+0.5t-9.5 Multiply through by 100.
8t%2B2830+=+50t-950 Subtract 8t from both sides.
2830+=+42t-950 Add 950 to both sides.
3780+=+42t Finally, divide both sides by 42.
highlight%28t+=+90%29
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2) Start with 2x+1 as the first odd number. (You can see that no matter what value x takes on, 2x+1 will give you an odd number), then the next consecutive odd numbers will be:
(2x+1)+(2x+3)+(2x+5)+(2x+7) = 120 Simplify and solve for x.
8x+16 = 120 Subtract 16 from both sides.
8x = 104 Divide both sides by 8.
x = 13.
The first odd integer is 2x+1 = 2(13)+1 = 27.
The second consecutive odd integer is 2x+3 = 2(13)+3 = 29.
The third consecutive odd integer is 2x+5 = 2(13)+5 = 31
The fourth consecutive odd integer is 2x+7 = 2(13)+7 = 33