Question 200651: 1. X^2-X-20/X^2-25/X^2-16/X^2-X-30
Please help me out
April
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! [ { X^2 -x -20} / {x^2-25} ] / [ {x^2 -16} / { x^2 -x -30} ]
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As with fractions, to divide invert and multiply,,,a/b/c/d = a/b * d/c
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[ { x^2 -x-20} / {x^2 -25}] * [ { x^2 -x -30} / {x^2 -16} ]
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factor and simplify by cancelling like terms
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[ { (x-5)(x+4)} / { (x+5)(x-5) } ] * [ { (x-6)(x+5) } / { ( x+4)(x-4)} ]
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( x-6) / (x-4),,,,,answer
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check,, let x=1,,,,in original = 1.5,,,,,,,in answer = 1.5,,,,,,ok
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